2x^2+x-20=-2x^2

Solution for 2x^2+x-20=-2x^2 equation:

2x^2+x-20=-2x^2

We move all terms to the left:

2x^2+x-20-(-2x^2)=0

We get rid of parentheses

2x^2+2x^2+x-20=0

We add all the numbers together, and all the variables

4x^2+x-20=0

a = 4; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·4·(-20)
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{321}}{2*4}=\frac{-1-\sqrt{321}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{321}}{2*4}=\frac{-1+\sqrt{321}}{8}
$